
Fig. 1. Whenever current passes through a component having resistance, a voltage exists across that component.
Look again at Fig. 1. There is a certain voltage across the resistor, not specifically indicated.
There’s also a current flowing through the resistance, and it is not quantified in the diagram, either. Suppose we call the voltage E and the current I, in volts (V) and amperes (A), respectively. Then the power in watts dissipated by the resistance, call it P, is the product of the voltage in volts and the current in amperes:
P = EI
If the voltage E across the resistance is caused by two flashlight cells in series, giving 3 V, and if the current I through the resistance (a light bulb, perhaps) is 0.1 A, then E = 3 V and I = 0.1 A, and we can calculate the power P in watts as follows:
P = EI = 3 × 0.1 = 0.3 W
Suppose the voltage is 117 V, and the current is 855 mA. To calculate the power, we must convert the current into amperes: 855 mA = 855/1000 A = 0.855 A. Then:
P = EI = 117 × 0.855 = 100 W